Sin^2x=5(cosx+1)

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Solution for Sin^2x=5(cosx+1) equation: 


Simplifying
Sin2x = 5(cosx + 1)

Reorder the terms:
in2xS = 5(1 + cosx)
in2xS = (1 * 5 + cosx * 5)
in2xS = (5 + 5cosx)

Solving
in2xS = 5 + 5cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by 'n2xS'.
i = 5n-2x-1S-1 + 5cn-2osS-1

Simplifying
i = 5n-2x-1S-1 + 5cn-2osS-1

Reorder the terms:
i = 5cn-2osS-1 + 5n-2x-1S-1

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